2X^2+5x-71=0

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Solution for 2X^2+5x-71=0 equation: 



2X^2+5X-71=0

a = 2; b = 5; c = -71;
Δ = b2-4ac
Δ = 52-4·2·(-71)
Δ = 593
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{593}}{2*2}=\frac{-5-\sqrt{593}}{4}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{593}}{2*2}=\frac{-5+\sqrt{593}}{4}
$

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